Among the many complex ions of cobalt are the following:Co(NH₃)₆³⁺(aq) +3en(aq) ⇄ Co(en)₃³⁺(aq) + 6NH₃(aq) where "en" stands for ethylenediamine, H₂NCH₂CH₂NH₂. Six Co-N bonds are broken and six Co-N bonds are formed in this reaction, so ΔH°rxn≈0; yet K>1. What are the signs of ΔS° and ΔG°? What drives the reaction?