give the product of the bimolecular elimination from each of the isomeric halogenated compounds. reaction a. the starting material consists of two chiral carbons bonded together. carbon 1 has an in plane bond to benzene pointing to the lower left, a wedged bond to hydrogen pointing up and a dashed bond to bromine pointing up. it is bonded to the other chiral carbon on the lower right. carbon 2 has a wedged bond to methyl pointing down, a dashed bond to hydrogen pointing down and an in plane bond to benzene pointing to the upper right. this reacts with potassium tert butoxide to form the product, tert butanol and bromide ion. reaction b. the starting material consists of two chiral carbons bonded together. carbon 1 has an in plane bond to benzene pointing to the lower left, a wedged bond to hydrogen pointing up and a dashed bond to bromine pointing up. it is bonded to the other chiral carbon on the lower right. carbon 2 has a dashed bond to methyl pointing down, a wedged bond to hydrogen pointing down and an in plane bond to benzene pointing to the upper right. this reacts with potassium tert butoxide to form the product, tert butanol and bromide ion. one of these compounds undergoes elimination 50x faster than the other. which one and why? reaction b because the conformation needed for elimination places the phenyl groups gauche to each other. reaction a because the conformation needed for elimination places the phenyl groups gauche to each other. reaction b because the conformation needed for elimination places the phenyl groups anti to each other. reaction a because the conformation needed for elimination places the phenyl groups anti to each other.