(Chapter 7 Section 1: Practice Problem 3, Randomized) (Data Entry: Use capital T for 8.) π/2 Find S cos sin³0 de and evaluate cos 0 sin³0 de -π/2 The ideal substitution in either case is u = The substitution changes the integrand in both integrals to some function of u, say (u)$; give the updated version of the indefinite integral: [G(u) du = [ du Having found the indefinite integral and returned to the original variable, the final result is: S cos 0 sin³0 de = For the definite integral, the substitution provides new limits of integration as follows: The lower limit L = π/2 becomes u The upper limit xy = π/2 becomes uy = The final value of the definite integral is: π/2 cos sin³0 de = -π/2 (Data Entry: Be sure to use capital +C as your arbitrary constant where needed.)