25.0 ml of 0.350 m naoh are added to 45.0 ml of 0.125 m copper (ii) sulfate. how many grams of copper (ii) hydroxide will precipitate?
2 NaOH₍ₐᵩ₎ + CuSO₄₍ₐᵩ₎ -> Cu(OH)₂₍ₛ₎ + Na2SO₄₍ₐᵩ₎