It (would, would not, would be​ unusual) because ​$51,320 is (more than 5, less than 1, between 3 and 4, between 2 and 3, between 4 and 5, between 1 and 2) standard​ error(s) away from the mean. A random sample with a​ z-score that (far from, close to, far from) zero is (highly unlikely, very likely).
According to a 2018 magazine, the average income in a state is $50,703. Suppose the standard deviation is $2,000 and the distribution of income is right-skewed. Repeated random samples of 400 are taken, and the sample mean income is calculated for each sample. Complete parts (a) through (c). a. The population distribution is right-skewed. Will the distribution of sample means be Normal? Why or why not? Since the conditions to the Central Limit Theorem are satisfied, the distribution is Normal because the sample size is large. b. Find and interpret a z-score that corresponds with a sample mean of $50,503. standard error(s) below the average income in the state. Since the standard error of the sampling distribution of the means is SE = $(the Z-score is S0, S50,503 is | (Type integers or decimals. Do not round.) Enter your answer in each of the answer boxes.