Does my work look right? 3. Parents that are carriers of a recessive trait have a 25% chance of having an offspring that expresses the recessive trait. If parents produce eight offspring, what is probability that one of the offspring will express the recessive trait? What is the probability that more than one offspring will express the recessive trait? Pr(x)=k!I(x!(k-x!))p*q(k-x) Pr(x)=8!/(8!(7!)).251.757 Pr(x)=40,320/(40,320(5040) ).25 x .1334 Pr(x)=0.0001984127 x .25 x .1334 Pr(x)=.00000617064 or 6.617064x10-6 For more than one (or at least two), we multiply the probabilities. We know the probability of one is 6.617064x10--.. So the probability of at least two would be 6.617064x10-6 x 6.617064x10-6 = 3.8076798x10-11