Show that the center of mass of a uniform rod of mass m and length l lies at the middle point of the rod. Limits:)l/2 to l/2.
a) ∫(x dm) from)l/2 to l/2 = 0
b) ∫(x dm) from)l/2 to l/2 = ml/2
c) ∫(x dm) from)l/2 to l/2 = ml
d) ∫(x dm) from)l/2 to l/2 = ml/4