Let A=
[ 1 sinθ 1 ]
[ −sinθ 1 sinθ ]
[ −1 −sinθ. 1 ] where 0≤θ≤2π. Then
Then

A Det(A)=0
B Det(A)∈(2,[infinity])
C Det(A)∈(2,4)
D Det(A)∈[2,4]