In Newton's Temperature Model, the response of the system is given by T = e⁻ᵏt ∫ eᵏs T_e(s)ds + T_0 e⁻ᵏtT(0)=T_0. The transient response, T_0 e⁻ᵏt, gradually declines as e⁻ᵏt approaches 0 as t approaches infinity. However, the steady-state response, e⁻ᵏt ∫ eᵏs T_e(s)ds, also has e⁻ᵏt multiplied to it. So, shouldn't this also approach 0 as t approaches infinity? How can this be called a steady-state solution? Additionally, how does the steady-state response approach 0 as t approaches 0 and why does the initial response depend only on the transient response?