leewalker2289 leewalker2289
  • 25-01-2024
  • Mathematics
contestada

If tanβ=ntanα/1+(1−n)tan2α then tan(α−β)=.
A. (1+n)tanα
B. (1-n)tanα
C. -(1+n)tanα
D. -(1-n)tanα

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