You throw a nerf basketball of mass 0.002 kg into the air. At =0, the ball leaves your hand. At =0.10 s, the net force on the ball is 〈−0.0190,−0.0232,0〉 N, its velocity is〈1.87,0.84,0〉 m/s, and its position is 〈0.325,0.105,0〉m. (Besides the gravitational force by Earth, air also exerts a force on the ball.)

Part 1. What will be its position at t = 0.12 s?
Part 2. At t =0.12 s, the net force on the ball is now 〈−0.0138,−0.0197,0〉 N. What will be its position at t = 0.14 s?