Hey Tierra7l,
Lets solve your equation together step by step.
[tex]3x+2\left(x-5\right)=50[/tex]
[tex]\mathrm{Expand}\:2\left(x-5\right):\quad 2x-10[/tex]
[tex]\mathrm{Distribute\:parentheses\:using}:\quad \:a\left(b+c\right)=ab+ac[/tex]
[tex]a=2,\:b=x,\:c=-5[/tex]
[tex]2\cdot \:x+2\left(-5\right)[/tex]
[tex]\mathrm{Apply\:minus-plus\:rules}[/tex]
[tex]\:\:+\left(-a\right)=-a[/tex]
[tex]2x-2\cdot \:5[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:2\cdot \:5=10[/tex]
[tex]2x-10[/tex]
[tex]3x+2x-10=50[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:3x+2x=5x[/tex]
[tex]5x-10=50[/tex]
[tex]\mathrm{Add\:}10\mathrm{\:to\:both\:sides}[/tex]
[tex]5x-10+10=50+10[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]5x=60[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}5[/tex]
[tex]\dfrac{5x}{5}=\dfrac{60}{5}[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]x=12[/tex]
Hope this helps,
AnthrαX
