Plz help me get the right answer to these

- [tex]b^{4}[/tex] + 6[tex]b^{3}[/tex]
divide each term on the numerator by 7b
= - 7[tex]b^{5}[/tex] / 7b + 42[tex]b^{4}[/tex] / 7b
= - [tex]b^{4}[/tex] + 6[tex]b^{3}[/tex]
Step-by-step explanation:
[tex](-7b^5+42b^4)\dib7b=\dfrac{-7b^5}{7b}+\dfrac{42b^4}{7b}=-b^4+6b^3[/tex]