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A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 30.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 14.0 mT in 0.20 s. Find the average electrical power dissipated in the process.(The resistivity of copper is 1.72 × 10 − 8 1.72×10−8 Ω . m Ω.m)

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umohduke14

Answer: 3 x 10^-24 watt

Explanation:

P ( resistivity) = 1.72e-8 (from the chart).

L= 2pi r

r= 30 cm.

R= pL/A

A= pi* r1^2

r1= 0.8118/2 * 10^-3 m

R= 1.68 x 10^-8 x (2x3.142x0.3)

= 3.24 x 10^-8

E=N do/dt

do= B* A

A= pi* 0.3^2

N=1

E = 1 x (14 x 3.142x 0.09) = 3.95

I=v/R

v=E,

I = 3.95 / 3.24 x 10^-8 = 1.22 x 10^8

P=I^2 x R.

= 3 x 10^-24 watt

lhmarianateixeira

In this exercise we have to use the knowledge of electrical power to calculate the value of the potency, so we have to:

The power is  3 x 10^-24 watt

How can we define power?

Power is a scalar physical quantity measured in watts (W). It can be defined as the rate of work performed each second or as the energy consumption per second. The watt, unit of power in the international system of units (SI), is equivalent to 1 joule per second.

Organizing some information from the utterance, we have that:

  • P  = 1.72e-8
  • L= 2pi r
  • r= 30 cm.

Are putting these values ​​in the formulas we will find that:

[tex]R= pL/A\\A= \pi* r1^2\\r1= 0.8118/2 * 10^-3\\R= 1.68 * 10^{-8} * (2*3.142*0.3)= 3.24 * 10^{-8}[/tex]

So the power is:

[tex]E = 1 * (14 * 3.142* 0.09) = 3.95\\I = 3.95 / 3.24 * 10^{-8} = 1.22 * 10^8\\P=I^2 * R= 3 * 10^{-24}[/tex]

See more about power at brainly.com/question/1618040

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