Answer:
[tex]\Delta G^{0}[/tex] at 181.0 [tex]^{0}\textrm{C}[/tex] is -723.3 kJ/mol.
Explanation:
We know, [tex]\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}[/tex]
where, T is temperature in kelvin.
Let's assume [tex]\Delta H^{0}[/tex] and [tex]\Delta S^{0}[/tex] does not change in the temperature range 25.0 [tex]^{0}\textrm{C}[/tex] - 181.0 [tex]^{0}\textrm{C}[/tex].
[tex]181.0^{0}\textrm{C}[/tex] = (273+181.0) K = 454.0 K
Hence, at 181.0 [tex]^{0}\textrm{C}[/tex], [tex]\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)][/tex]
= -723.3 kJ/mol
