Answer:
-2y = 4 - x
2y = x - 4
y = 1/2x - 2
1/2 is the slope of both lines.
y = mx + b
Substitute the given point and the common slope
2 = 1/2 x 2 + b
2 = 1 + b
b = 1
y = 1/2x + 1
The equation of the line that passes through the point
(2, 2) and is parallel to the line x - 2y = 4 is y = 1/2x + 1 or 2y = x + 2.
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Answer:
x - 2y = - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 2y = 4 ( subtract x from both sides )
- 2y = - x + 4 ( divide all terms by - 2 )
y = [tex]\frac{1}{2}[/tex] x - 2 ← in slope- intercept form
with slope m = [tex]\frac{1}{2}[/tex]
Parallel lines have equal slopes, thus
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute (2, 2) into the partial equation
2 = 1 + c ⇒ c = 2 - 1 = 1
y = [tex]\frac{1}{2}[/tex] x + 1 ← equation in slope- intercept form
Multiply through by 2
2y = x + 2 ( subtract 2y from both sides )
0 = x - 2y + 2 ( subtract 2 from both sides )
- 2 = x - 2y, that is
x - 2y = - 2 ← equation in standard form
