What is sec 0 when tan 0 = V3? Đ. (1, 0) sec 0 = [?]

Answer:
secθ = - 2
Step-by-step explanation:
Using the identity
sec²θ = 1 + tan²θ
= 1 + ([tex]\sqrt{3}[/tex] )² = 1 + 3 = 4 ( take the square root of both sides )
secθ = ± [tex]\sqrt{4}[/tex] = ± 2
Since secθ < 0 in the third quadrant , then
secθ = - 2