Respuesta :

             [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

          Write the equation of a line perpendicular to y=-12x+2 going

           through (0, -1)

     [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]

        First, let's take a look at our provided information:-

  • A line [tex]\text{y=-12x+2}[/tex]
  • A point (0, -1)
  • The line [tex]\text{y=-12x+2}[/tex] is perpendicular to the line that goes through (0, -1)

     If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

   So we take the slope of the given line, which is -12, change its sign from minus to plus:-

[tex]\Large\textit{12}[/tex]

And now, We flip the number over:-

[tex]\Large\text{$\displaystyle\frac{1}{12}$}[/tex]

Now that we've found the slope of the line, let's find its equation.

     The first step is to write it in point-slope form as follows:-

[tex]\longmapsto\sf{y-y_1=m(x-x_1)}[/tex]

Replace letters with numbers,

[tex]\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}[/tex]

On simplification,

[tex]\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}[/tex]

On further simplification,

[tex]\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}[/tex]

Subtracting 1 on both sides,

[tex]\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}[/tex]

[tex]\Uparrow\texttt{Our equation in slope-intercept form}[/tex]

Good luck with your studies.

#TogetherWeGoFar

[tex]\rule{300}{1}[/tex]

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