⁵/₁₂ hours
Given:
Question:
How much longer did Jean-Luc take than William in hours?
The Process:
Let us prepare [tex]\boxed{1\frac{1}{4} = \frac{5}{4}}[/tex] as a jogging time from Jean-Luc.
We have to do a subtraction between two fractions to find out how much longer did Jean-Luc take than William in hours.
Previously, we must equate the denominator. We know that the least common multiple (LCM) of 4 and 6 is 24.
SInce [tex]\boxed{\frac{30}{24} > \frac{20}{24}}[/tex], then Jean-Luc takes longer than William.
Let us calculate the subtraction between these two fractions.
[tex]\boxed{ \ 1\frac{1}{4} - \frac{5}{6} = \ ? \ }[/tex]
[tex]\boxed{ \ = \frac{5}{4} - \frac{5}{6} \ }[/tex]
[tex]\boxed{ \ = \frac{5 \times 6}{4 \times 6} - \frac{5 \times 4}{6 \times 4} = \ }[/tex]
[tex]\boxed{ \ = \frac{30}{24} - \frac{20}{24} \ }[/tex]
[tex]\boxed{ \ = \frac{30 - 20}{24} \ }[/tex]
[tex]\boxed{ \ = \frac{10}{24} \ }[/tex]
Simplify it. The numerator and denominator are divided by two.
[tex]\boxed{\boxed{ \ \frac{5}{12} \ }}[/tex]
Thus, Jean-Luc takes [tex]\frac{5}{12}[/tex] hours longer than William.
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