in a titration 5.0 mL of a 2.0 M NaOH(aq) solution exactly neutralizes 10.0 mL of an HCI(aq) solution. What is the concentration of the HCI(aq) solution?
Volume of base(NaOH)= Vb =5 mL Concentration of base(NaOH)= Mb =2 M Volume of acid(HCl)= Va =10 mL Concentration of acid(HCl)= Ma = ? Now, Ma*Va = Mb*Vb Ma*(10) = (2)*(5)