1) (y^2-2y+1)/(2y-3)
2y-3=0
Solving for y:
2y-3+3=0+3
2y=3
2y/2=3/2
y=3/2
2) y(y+5)/(4y+1)
4y+1=0
Solving for y:
4y+1-1=0-1
4y=-1
4y/4=-1/4
y=-1/4
3) (5y^2-6y+1)/[-5(y-1)]
-5(y-1)=0
Solving for y:
-5(y-1)/(-5)=0/(-5)
y-1=0
y-1+1=0+1
y=1
4) (y^2-y-6)/[-2(y+7)]
-2(y+7)=0
-2(y+7)/(-2)=0/(-2)
y+7=0
y+7-7=0-7
y=-7
Pairs
-7 → (y^2-y+6)/[-2(y+7)]
3/2 → (y^2-2y+1)/(2y-3)
1 → (5y^2-6y+1)/[(-5(y-1)]
-1/4 → y(y+5)/(4y+1)
