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Given: AC and AE are common external tangents of G and D. FE = 26, GF = 5, and AG = 13.

What is the measure of AC?

Given AC and AE are common external tangents of G and D FE 26 GF 5 and AG 13 What is the measure of AC class=

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SINAZEUS
the answer is 38



FG is 5. so BG is 5,too

FE = 26. so BC =26

now we should find AB with Pythagorean theorem:
[tex] {5}^{2} + x {}^{2} = 13 {}^{2} \\ {x}^{2} = {13}^{2} - {5}^{2} \\ {x}^{2} = 169 - 25 = 144 [/tex]
[tex]x = \sqrt{144} = 12[/tex]
AB is 12
BC is 26
so AC is 12+26=38


good luck

Answer:

26

Step-by-step explanation: I Took the test


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