Answer:
8.0 * 10⁻¹⁰ F
Explanation:
The energy, charge and capacitance can be related using the following formula:
[tex]U = \frac{1}{2} * \frac{Q^2}{C} [/tex]
where:
U is the energy given = 2.4 * 10⁻⁶ J
Q is the charge given = 6.2 * 10⁻⁸ C
C is the value of capacitance we want to find
Substitute with the givens in the above equation to get the capacitance as follows:
[tex]U = \frac{1}{2} * \frac{Q^2}{C} [/tex]
2.4 * 10⁻⁶ = [tex] \frac{1}{2} * \frac{(6.2*10^-8)^2}{C} [/tex]
(6.2 * 10⁻⁸)^2 = 2 * 2.4 * 10⁻⁶ * C
C = [tex] \frac{(6.2*10^-^8)^2}{2*2.4*10^-^6} = 8.0 * 10^-^1^0 F[/tex]
Hope this helps :)
