Thomas was selling tickets to his school play. The tickets cost $5.00 for adults and $2.00 for children. He sold 200 tickets and collected $610. Which system represents the number of adult and child tickets that Thomas sold?

Respuesta :

adult: $5, qty x
children: $2, qty y
total: $610, qty 200

Cost:      5x + 2y = 610
Quantity:  x +   y = 200

Using elimination method to solve the system of equations:
 1(5x + 2y = 610) →  5x + 2y = 610
-2( x  +  y  = 200) → -2x - 2y = -400
 Add both equations: 3x + 0  = 210
 Divide both sides by 3: x = 70

Substitute "x = 70" into either the Cost or Quantity equation: 
Quantity: x + y = 200 → 70 + y = 200 → y = 130

Adult tickets sold = 70
Children tickets sold = 130

Thomas sold 70 adult and 130 child tickets.

Total revenue through an Item

The total revenue through an item is the product of its cost per unit and the number of units sold.

[tex]\bold{Total\ revenue = (Cost/unit)\times {Number\ of\ units\ sold}}[/tex]

Given to us,

Ticket cost for adults = $5.00,

Ticket cost for children = $2.00

Total number of ticket sold = 200

Total revenue generated = $610

Assumption

Let's assume that the number of adults tickets sold is x, and the number of children tickets sold is y.

Total number of tickets sold

Total number of tickets sold

                                 = Ticket cost for adults + Ticket cost for children

Substituting the values,                          

200 = [tex]x+y[/tex]

[tex]x= 200 - y[/tex]

Total revenue generated

Revenue generated through adult ticket

                      = Ticket cost for adults x number of adults tickets sold

                      = [tex]\$5 \times x[/tex]  =  [tex]5x[/tex]

Revenue generated through children ticket

                      = Ticket cost for children x number of children tickets sold

                      = [tex]\$2 \times y[/tex]  =  [tex]2y[/tex]

Total revenue generated

= Revenue through adult ticket +Revenue through children ticket

Substituting the values,

[tex]610 = 5x + 2y[/tex]

Substituting the value of x,

[tex]610 = 5(200-y) + 2y\\610 = 1000-5y + 2y\\610-1000 = -3y\\-390 = -3y\\y = \dfrac{390}{3}\\y = 130[/tex]

Substituting the value of y,

[tex]x = 200- y \\x = 200 -130\\x=70\\[/tex]

Hence, Thomas sold 70 adult and 130 child tickets.

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