Answer:
The value of x are [tex]\frac{13+\sqrt{29}}{10}[/tex] and [tex]\frac{13-\sqrt{29}}{10}[/tex].
Step-by-step explanation:
The given equation is:
[tex]5x^2-13x+7=0[/tex]
Solving the above equation using the quadratic formula, we get
[tex]x=\frac{-(-13){\pm}\sqrt{(-13)^2-4(5)(7)}}{2(5)}[/tex]
[tex]x=\frac{13{\pm}\sqrt{(169-140)}}{10}[/tex]
[tex]x=\frac{13{\pm}\sqrt{29}}{10}[/tex]
Thus, the value of x are [tex]\frac{13+\sqrt{29}}{10}[/tex] and [tex]\frac{13-\sqrt{29}}{10}[/tex].
which is the required simplified form of the given expression.
