Answer:
20 L of NH₃ at S.T.P
Solution:
The balance chemical equation is as follow,
4 NH₃ + 6 NO → 5 N₂ + 6 H₂O
According to equation,
134.4 L (6 mole) NO is required = 89.6 L (4 moles) NH₃ gas at S.T.P
So,
30 L of NO will require = X L of NH₃ at S.T.P
Solving for X,
X = (30 L × 89.6 L) ÷ 134.4 L
X = 20 L of NH₃ at S.T.P
