Answer:
[tex]AC=11\frac{\sqrt{3}}{3}\ units[/tex] or [tex]AC=6.35\ units[/tex]
Step-by-step explanation:
we know that
In the right triangle ABC
AC and BC are the legs of the triangle
AB is the hypotenuse
see the attached figure to better understand the problem
[tex]tan(30\°)=\frac{AC}{BC}[/tex]
[tex]tan(30\°)=\frac{\sqrt{3}}{3}[/tex]
so
[tex]\frac{\sqrt{3}}{3}=\frac{AC}{BC}[/tex]
[tex]AC=\frac{\sqrt{3}}{3}BC[/tex]
substitute the value of BC
[tex]AC=\frac{\sqrt{3}}{3}(11)[/tex]
[tex]AC=11\frac{\sqrt{3}}{3}\ units[/tex]
[tex]AC=6.35\ units[/tex]
