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Construction workers are installing a rectangular, in-ground pool. To start, they dig a rectangular hole in the ground where the pool will be. The area of the ground that they will be digging up is 252 square feet. The length of the pool is twice the width of the pool. What are the dimensions of the pool? Round to the nearest tenth

Respuesta :

tramserran
Length (L) = 2 · W
Width (W) = W
Area (A) = L · W
       252 = (2W)(W)
       252 = 2W²
       126 = W²
       11.2 ≈ W
L = 2 · W
   = 2 · 11.2
   = 22.4

Dimensions: 11.2 ft x 22.4 ft

Length (l) = 22 feets and Breadth (b) = 11 feets  when we round to the nearest tenth.

Rectangle:

A rectangle is a 2D shape that has 4 sides, 4 corners, and 4 right angles. Opposite sides of a rectangle shape are the same length, with one pair being longer than the other pair.

Area of rectangle = l x b

Lets take breadth or width of a rectangle  be b.

(Given), length of a rectangle (l) = twice of width

=> l = 2 x b.

Area of rectangle = l x b

(Given) Area of the rectangle = 252 square feets

252 = (2 x b) x b

252 = 2 x [tex]b^{2}[/tex]

[tex]\frac{252}{2}[/tex] = [tex]b^{2}[/tex]

126 = [tex]b^{2}[/tex]

b = [tex]\sqrt{126}[/tex] = 11.22

So, l = 2 x b = 22.44

l = 22 and b = 11 (Rounded to the nearest tenth).

Learn more about  area of rectangle here: https://brainly.com/question/17673166?referrer=searchResults

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