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Andy had a snowball (a perfect sphere) with a radius of 3 \text{ cm}3 cm3, space, c, m. he wanted the snowball to be bigger, so he spent 444 seconds packing more snow onto it. each second he spent packing, the snowball's radius increased by 0.25 \text{ cm}0.25 cm0, point, 25, space, c, m. what is the ratio of the current volume of the snowball to the original volume of the snowball? choose 1 answer:

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The original volume is given by:
 V1 = (4/3) * (pi) * (r1 ^ 3)
 V1 = (4/3) * (3.14) * (3 ^ 3)
 V1 = 113.04 cm ^ 3
 The current volume is given by:
 V2 = (4/3) * (pi) * ((r1 + 0.25 * t) ^ 3)
 V2 = (4/3) * (3.14) * ((3 + 0.25 * 4) ^ 3)
 V2 = 267.9466667 cm ^ 3
 The relation of volumes is:
 V2 / V1 = 64/27
 Answer:
 The ratio of the current volume of the snowball to the original volume of the snowball is:
 V2 / V1 = 64/27

The ratio of the current volume of the snowball to the original volume of the snowball is 64/27.

We have given that,r1=3

What is the formula for volume?

[tex]V = (4/3) * (pi) * (r ^ 3)[/tex]

The original volume is given by:

[tex]V_1 = (4/3) * (pi) * (r_1 ^ 3)[/tex]

[tex]V_1 = (4/3) * (3.14) * (3 ^ 3)[/tex]

[tex]V_1 = 113.04 cm ^ 3[/tex]

Next, we have to find the current volume

The current volume is given by,

[tex]V_2 = (4/3) * (pi) * ((r_1 + 0.25 * t) ^ 3)[/tex]

[tex]V_2 = (4/3) * (3.14) * ((3 + 0.25 * 4) ^ 3)[/tex]

[tex]V_2 = 267.9466667 cm ^ 3[/tex]

The relation of volumes is given by,

V2 / V1 = 64/27

The ratio of the current volume of the snowball to the original volume of the snowball is 64/27.

To learn more about the volume visit:

https://brainly.com/question/1972490

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