The derivative is calculated as -0.19865.
Antiderivatives
It is opposite to the derivative.
Derivative
The rate of change of a function with respect to a variable.
Given
[tex]\rm Antiderivative=sin\dfrac{1}{x^{2} +1} [/tex]
How to calculate the antiderivative?
[tex]\int\limits^2_1 {f(x)} \, dx = sin\dfrac{1}{2^{2} +1} - sin\dfrac{1}{1^{2} +1} \\
\int\limits^2_1 {f(x)} \, dx = sin\dfrac{1}{5} - sin\dfrac{1}{2}\\
\int\limits^2_1 {f(x)} \, dx = 0.19866-0.47942\\
\int\limits^2_1 {f(x)} \, dx = -0.19865[/tex]
Thus, the derivative is calculated as -0.19865.
More about the antiderivatives link is given below.
https://brainly.com/question/15522062
