It is given in the question that
A spinner is divided into 11 equal sections from 0 to 10. you spin the spinner once.
And number of even numbers in 0 to 10 is 6.
Total number of possibilities is 6 and total number of sample space is 11.
So the probability of getting an even number is
[tex]p(even) = \frac{6}{11}[/tex]
