Respuesta :

DWJ2
For the function f ( x ) = x² we have the new function f 1 ( x ) = 1/2 x².f ( x ) = a · x²- If |a| < 1   the graph is compressed vertically by a factor of a.- If |a| > 1  the graph is stretched vertically by a factor of a.Here:  a = 1/2 < 1

Answer:C. The graph will be compressed vertically.

Answer: The graph of f(x) would shrink vertically by [tex]\dfrac{1}{3}\ units[/tex].

Step-by-step explanation:

Since we have given that

[tex]f(x)=x^2[/tex]

We need to multiply f(x) by [tex]\dfrac{1}{3}[/tex]

Let f(x) = y.

We have two conditions :

y=kf(x)

if k>1, then it tends to vertical stretch.

if k<1, then it tends to vertical shrink.

Since we have given that we have to multiply [tex]\dfrac{1}{3}[/tex] with f(x) as [tex]\dfrac{1}{3}<1[/tex]

so, it tends to vertical shrink, and it move closer to x-axis which make the graph flatter.

Hence, the graph of f(x) would shrink vertically by [tex]\dfrac{1}{3}\ units[/tex].

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