The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

Respuesta :

kanest
Initial velocity means that the time will be 0 seconds.

We must derive the equation first to find velocity:

[tex] \frac{d}{dt} -16t^{2} + 19t + 110[/tex]
[tex]-32t + 19[/tex]

Because we're looking for initial velocity, t = 0. Plug this into the equation:

[tex]-32(0) + 19[/tex]
[tex]0 + 19 = 19[/tex]

The initial velocity of the rock thrown is 19 feet per second.