I am doing with Question Number 2
Let the two numbers be 'x' and 'y'.
According to the question, the product of two numbers is 14.
[tex] x \times y=14 [/tex]
So, xy=14 (Equation 1)
Now, one of the numbers is 3 ½ times the other.
So, [tex] x = 3\frac{1}{2}\times y [/tex]
[tex] x=\frac{7}{2}y [/tex] (Equation 2)
Substituting the value of 'x' from equation 2 in equation 1, we get
[tex] \frac{7}{2}y \times y = 14 [/tex]
[tex] \frac{7}{2}y^{2} = 14 [/tex]
[tex] y^{2} = 4 [/tex]
So, y= 2 and -2
So, [tex] x=\frac{14}{2} [/tex] and [tex] x=\frac{14}{-2} [/tex]
x=7 and -7
Numbers are 2,7 and -2,-7.
Sum of numbers 2 and 7 = 9
Sum of numbers -2 and -7 = -9.