Respuesta :

kenmyna
the temperature that  would  the volume of a gas  be 0.550l  if  it  had a volume of 0.432 L  at  -20.0  c is calculated  using the Charles law formula

that is   v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l

by  making T1  the subject of the formula  T1= V1T2/V2


T1=  (0.55lL x253)/  0.432 l = 322.11 K  or  322.11-273 = 49.11 C

Answer: 321.6 K

Explanation: Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]    (At constant pressure and number of moles)

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 0.432 L

[tex]V_2[/tex] = final volume of gas = 0.550 L

[tex]T_1[/tex] = initial temperature of gas = [tex]-20^oC=273-20=253K[/tex]

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

[tex]\frac{0.432L}{253K}=\frac{0.550L}{T_2}[/tex]

[tex]T_2=321.6K[/tex]

Therefore, the final temperature will be 321.6 K.