I am assuming that you are rolling two dice.
Probability of even: 18 "evens" out of 36 total outcomes = 18/36
→(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5),(4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)
Probability of greater than 9: 6 ">9s" out of 36 total outcomes = 6/36
→(4,6), (5,5), (5,6), (6,4), (6,5), (6,6)
Probability of both evens and >9s: 4 "both" out of 36 total outcomes = 4/36
→(4,6), (5,5), (6,4), (6,6)
evens OR >9s NOT both
[tex] \frac{18}{36} [/tex] + [tex] \frac{6}{36} [/tex] - [tex] \frac{4}{36} [/tex] = [tex] \frac{20}{36} [/tex] = [tex] \frac{5}{9} [/tex]
Answer: [tex] \frac{5}{9} [/tex]
