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Trapezoid JKLM is shown on the coordinate plane below: Trapezoid JKLM on the coordinate plane with ordered pairs at J negative 7, negative 2, at K negative 4, negative 2, at L negative 2, negative 5, at M negative 9, negative 5. If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y − 3), what are the coordinates of point L'? (1, −5) (−10, 6) (−5, 3) (6, −8)

Respuesta :

kathyweird
The answer is (6, -8). You add 8 to the x coordinate of vertex L and subtract 3 from its y coordinate.

Answer:

The correct option is 4.

Step-by-step explanation:

The vertices of trapezoid JKLM are J(-7,-2), K(-4,-2), L(-2,-5), M(-9,-5).

The translation is defined by the rule

[tex](x,y)\rightarrow (x+8,y-3)[/tex]

The coordinates of point L are (-2,-5), so the coordinates of L' are

[tex]L(-2,-5)\rightarrow L'(-2+8,-5-3)[/tex]

[tex]L(-2,-5)\rightarrow L'(6,-8)[/tex]

The coordinates of L' are (6,-8).

Therefore the correct option is 4.

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