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If you made up a solution of NaOH by adding 0.010 mole of solid NaOH to 1.0 liter of distilled water, what would be the concentration of the OH-(aq)?

Respuesta :

Ishankahps
Answer is 0.01 M.

Explantion :

NaOH is a strong base which fully dissociates into its ions in water as Na⁺ and OH⁻.

NaOH(s) → Na⁺(aq) + OH⁻(aq)

The stoichiometric ratio between NaOH(s) and OH⁻(aq) is 1 : 1.

Hence, 
   moles of OH⁻(aq) = moles of NaOH(s)
                                = 0.010 mol

Concentration (M) = moles of solute (mol) / volume of the solution (L)

Hence,
    concentration of OH⁻(aq) = 0.010 mol / 1.0 L
                                             = 0.01 M

Answer:

0.01M OR  1 x10 ^-2M

Explanation:

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