Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
The value of b is -21. To find the slope of the line use the slope formula: [tex] \frac{y^2 - y^1}{ x^{2} - x^1} [/tex]. The slope is -4. Then you plug in one coordinate to find the value of b.
