Respuesta :
The first thing we must do for this case is to identify the function that models the table.We have a function of the form:
[tex]f (x) = mx + b [/tex]
Where,
m: slope of the line
b: cutting point with the y axis
We observe that for x = 0 the value of the function is f (0) = 3/2. From here, it is concluded:
[tex]b = 3/2 [/tex]
Then, the change of rate is constant and equal to 1/2, therefore,
[tex]m = 1/2 [/tex]
So, the function is:
[tex]f (x) = (1/2) x + 3/2 [/tex]
Therefore, we have:
[tex]f (-1/2) = (1/2) (- 1/2) + 3/2 = 5/4 f (0) = (1/2) (0) + 3/2 = 3/2[/tex]
[tex]f (1) = ((1/2) (1) + 3/2 = 2 f (2) = (1/2) (2) + 3/2 = 5/2 f (4) = (1/2) (4) + 3/2 = 7/2[/tex]
Answer:
statements that are true of the given function:
[tex]f (0) = 3/2 f (4) = 7/2[/tex]
[tex]f (x) = mx + b [/tex]
Where,
m: slope of the line
b: cutting point with the y axis
We observe that for x = 0 the value of the function is f (0) = 3/2. From here, it is concluded:
[tex]b = 3/2 [/tex]
Then, the change of rate is constant and equal to 1/2, therefore,
[tex]m = 1/2 [/tex]
So, the function is:
[tex]f (x) = (1/2) x + 3/2 [/tex]
Therefore, we have:
[tex]f (-1/2) = (1/2) (- 1/2) + 3/2 = 5/4 f (0) = (1/2) (0) + 3/2 = 3/2[/tex]
[tex]f (1) = ((1/2) (1) + 3/2 = 2 f (2) = (1/2) (2) + 3/2 = 5/2 f (4) = (1/2) (4) + 3/2 = 7/2[/tex]
Answer:
statements that are true of the given function:
[tex]f (0) = 3/2 f (4) = 7/2[/tex]
Answer:
The answer is B. and E. the only fractions on there
Step-by-step explanation: