Respuesta :

carlosego
For this case we have the following inequality:
 [tex] \frac{x-9}{7x+2} \leq 0[/tex]
 Solving for the numerator we have:
 [tex]x-9 \leq 0[/tex]
 [tex]x \leq 9[/tex]
 Solving for the denominator we have:
 [tex]7x+2\ \textgreater \ 0[/tex]
 [tex]7x\ \textgreater \ -2[/tex]
 [tex]x \ \textgreater \ \frac{-2}{7} [/tex]
 Therefore, the solution is given by:
 [tex] \frac{-2}{7} \ \textless \ x \leq 9 [/tex]
 The graph that shows this solution is the graphic number 3.
 Answer:
 option 3
calculista
we have that
(x-9)/(7x+2)<=0

we know that
the denominator cannot be zero, therefore the value of x = -2 /7 cannot belong to the domain of the function
7x+2=0-----> x=-2/7-----> x=-0.29

using a graph tool
see the attached figure

the solution is the interval
(-2/7, 9]---------> (-0.29, 9]
the value of -0.29 is not included in the solution

therefore 
the answer is the third option

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