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AL2006
We want to know the amount of force that stretches the spring 0.22 m.
That force is the WEIGHT of the mass hung from it.
The weight of the mass is (mass) times (gravity).
To do that calculation, we need to know the value of gravity, but
gravity has different values on every planet.  I shall assume that
this whole springy question is taking place on Earth, so that the
value of gravity is 9.8 m/s² .

The weight of the mass is (0.4 kg) x (9.8 m/s²) = 3.92 Newtons.

The spring constant is

(force/length of the stretch)

= (3.92 Newtons) / (0.22 meters)

= (3.92 / 0.22) Newtons/meter

= 17.82 N/m .

Spring constant is the measure of spring stiffness. The value of spring constant is 17.83 newton per meter.

Given information-

The length of spring stretches 0.220.

The mass of the object which hung on spring is 0.400 kg.

The spring constant has to find out.

What is spring constant?

Spring constant is the measure of spring stiffness.

Spring constant is the ratio of the force applied on the spring to the displacement of spring after the force has been applied. It can be given as,

[tex]k=\dfrac{F}{x}[/tex]

Here the force acting on the body is weight of the body. The weight of the body is the product of mass [tex]m[/tex] and gravitational force [tex]g[/tex]. Hence,

[tex]k=\dfrac{mg}{x}[/tex]

As the value of the gravitational force is 9.81 meter per second squared. Put the values,

[tex]k=\dfrac{0.400\times9.81}{0.220}\\k=17.83[/tex]

Hence the value of spring constant is 17.83 newton per meter.

Learn more about the spring constant here;

https://brainly.com/question/4291098

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