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Which function’s domain consists of all real numbers greater than 3?

A) f(x) = 3x

B) f(x) = the square root of x

C) f(x) = 3x + 4

D) f(x) = 1 over the square root of x - 3

Respuesta :

WojtekR
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.

Answer:

[tex]f(x)=\frac{1}{x-3}[/tex]

Step-by-step explanation:

find function that consist of domain = all real numbers greater than 3

A) [tex]f(x) = 3x[/tex]

f(x) is a linear function, for all linear function the domain is set of all real numbers.

B)  [tex]f(x)= \sqrt{x}[/tex]

For square root function , the domain is set of all real numbers greater than 0

C) [tex]f(x) = 3x + 4[/tex]

 f(x) is a linear function, for all linear function the domain is set of all real numbers.

D)  [tex]f(x)=\frac{1}{x-3}[/tex]

for square root function we set x-3>0 and solve for x

x > 3, so domain is all real numbers greater than 3

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