Respuesta :

mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
                = 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
                     = 6.97 g
The answer is 7.0 grams of water