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The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to

gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is –9.8 m/s2.

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

The projectile motion of an object can be modeled using ht gt2 v0t h0 where g is the acceleration due to gravity t is the time since launch ht is the height of class=

Respuesta :

erinwebsterrr
The answer is C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

option C

Step-by-step explanation:

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity. The acceleration due to gravity is –9.8 m/s2

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

g= -9.8, v0 = 20  and h0 = 60

So the equation becomes

[tex]h(t)= -9.8t^2 +20t +60[/tex]

When the object hit the ground the height =0 so we replace h(t)=0

Apply quadratic formula

[tex]t= \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]

a= -9.8 , b=20  and c= 60

[tex]t= \frac{-20+-\sqrt{(20)^2-4(-9.8)(60)}}{2(-9.8)}[/tex]