Answer : As given in the question the concentration of acid and base are in equimolar proportion so,
the simple net ionic reaction that the system is undergoing can be given as,
[tex] H^{+} _{(aq.)} + OH^{-} _{(aq.)} ----\ \textgreater \ H_{2} O + heat[/tex]
we can now calculate the total number of moles reacting in the species as,
(30 mL) X (1L/1000ML) X 0.150 moles = [tex] 4.5 X 10 ^{-3} [/tex] moles.
Now, we know the specific heat of water as 4.186 J/g °C.
Now considering the total volume of the product as 60 mL or 60 g (as it is water it can be g or mL) hence, ΔC is 2.5 C.
Now converting these into joules = 4.186 J/g °C X 2.5 X 60 = 627.9 Joules.
On dividing this we get 627.9 Joules / [tex] 4.5 X 10 ^{-3} [/tex] moles = 140 KiloJoules/mole.
So the answer is 140 KJ/M.
