Our three consecutive integers can be represented as
X → first integer
X + 1 → second integer
X + 2 → third integer
If the sum of our three consecutive integers is 141, our equation will read...
X + X + 1 + X + 2 = 141
Now, we can simplify on the left. Once we simplify, our equation will now read
3x + 3 = 141
-3 -3 ← subtract 3 on both sides
3x = 138 ← divide by 3 on both sides
X = 46 ← smallest integer
Therefore, the smallest integer is 46.
