Find a linear equation that expresses the relationship between the temperature in degrees Celsius C and degrees Fahrenheit F. Use the fact that water freezes at 0°C (32°F) and boils at 100°C (212°F). Use the equation to convert 94°F to degrees Celsius. (Round your answer to one decimal place.)

Respuesta :

Hello!

As we can see, to get 0 to 32 we add 32. With the boiling point, though, adding thirty two will not do the trick. We may have to add another step. If we subtract 32 from 212 we get 180. To get 100 to 180, we multiply by 1.8, which is equivalent to 9/5.

This gives us the equation F=1.8C+32. If we wanted to convert to Celsius we solve the equation for C.

F=1.8C+32-32
F-32=1.8C
(F-32)÷1.8=C

Now we will plug our Fahrenheit into the equation to convert to Celsius

(94-32)÷1.8=C
62/1.8=C
34.4≈C

Our answer is about 34.4°C.

I hope this helps!

  1. The linear equation that connect temperature in degree Celsius and degree Fahrenheit is [tex]F = 1.8C + 32[/tex]
  1. The temperature in degree Celsius is [tex]34.44 \ ^0C[/tex]

The linear equation from the given parameters:

[tex]0^0C = 32^0F \ and\\\\100^0C = 212 ^0F \\\\ the \ linear \ relationship \ is \ calculated \ as \ follows \ using \ \\interpolation \ method\\\\ \frac{C - 0 }{100 -0} = \frac{F-32}{212-32} \\\\\frac{C}{100} = \frac{F-32}{180} \\\\100(F-32) = 180C\\\\divide \ through \ by \ 100\\\\F-32 = 1.8C\\\\Add \ 32 \ to \ both \ sides\\\\F = 1.8C + 32[/tex]

Find the temperature in degree Celsius, When F =  94°F, C = ?

[tex]F = 1.8C + 32\\\\1.8C = F-32\\\\C = \frac{F-32}{1.8} \\\\C = \frac{94-32}{1.8} \\\\C = 34.44 \ ^0C[/tex]

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