The PH of 1.0 x10^-5 solution of sulfuric acid(H2SO4) is 4.7
calculation
PH =-log (H^+)
to calculate (H^+) concentration
write the equation for dissociation of H2so4
H2SO4⇔ 2H^+ + SO4^2-
if the concentration of H2SO4 = 1.0 x10^-5 and the mole ratio between H2SO4 to H^+ is 1:2 therefore the concentration of H^+
= 2 x(1.0 x10^-5)= 2 x10^-5 M
therefore Ph =- log (2x10^-5) = 4.7
