As the variation is direct then we have the following expression: [tex]y = kx ^ 2
[/tex] From here, we clear the value of k. For this we use the following data: y = 144 when x = 4 Substituting values: [tex]144 = k4 ^ 2
[/tex] Clearing k we have: [tex]k = 144/4 ^ 2
k = 144/16
k = 9[/tex] Then, the function is: [tex]y = 9x ^ 2
[/tex] When x = -5 we have: [tex]y = 9 (-5) ^ 2
y = 9 (25)
Y = 225[/tex] Answer: the value of y when x = -5 is: b. 225